Crisanquito <
[email protected]> wrote:
>I mean, it is evident how gaussian noise affects the received complex
>symbols and its conditional density is easily computed, but P(bit
>j of the receivedcodeword|bit j of the transmittedcodeword)=
>P(ykl|xkl)? I do not see it.
This is a little difficult because you actually don't have a
probability, you have a measure. People sometimes say things
like "the probability of receiving signal X given that a certain
transmitted bit is a one" but obviously the probability of
receiving a given signal point is always zero. So what you
need to do is construct a measure m0 for the zero-transmitted-bit
case and m1 for the one-transmitted-bit case, and state
the "probability of a one" as m1/(m0+m1). These meausres are
constructed by fixing one of the transmitted bits within the QAM
symbol, letting the other bits range over their possible values
(which are equiprobable, comprising half of the total number of
constellation points), and adding up the individual densities.
This leads to equations like I stated earlier.
Is this rigorous? Not really sure, but it gives you the right answer.
Practically speaking if your turbo or LDPC decoder is performing
close to capacity (within one dB) then you probably constructed
the measures correctly.
Steve