inverse Fourier for pulse shaping filter

[CW]

This is probably a very basic question, but how do i derive the
inverse Fourier transform for the following

G(f) = [1+T abs(f) ( sinc(2 f T) - 1)] / sinc(f T), for abs(f) <= 1/T

and zero elsewhere.

If i plug this into the IFT formula i end up with

1/T
g(t) = int G(f) e^j2pi f t df
-1/T

and when i substitute for G(f) above i can take out the first and
second terms but where do i go from there?

1/T
g(t) = 1+T * int abs(f) ( sinc(2 f T) - 1)] / sinc(f T)
-1/T

Can i simplify the equation somehow? Thanks for any help.

CW

[robert bristow-johnson]

On May 28, 3:40 pm, CW <[email protected]> wrote:
>
> 1/T
> g(t) = 1+T * int abs(f) ( sinc(2 f T) - 1)] / sinc(f T)
> -1/T
>

you're a little sloppy with unmatched parenths or brackets.

> Can i simplify the equation somehow?

bust the integral into two, one from -1/T to 0 (where |f| = -f) and
another from 0 to +1/T (where |f| = f). you still have other ickies
to worry about.

> Thanks for any help.

yer wekcine.

r b-j